f (x) = [x²+1]/[x²-1] i got f ''(x) = [12x²+4]/[(x²-1)^3]
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Originally Posted by maybnxtseasn f (x) = [x²+1]/[x²-1] i got f ''(x) = [12x²+4]/[(x²-1)^3] Use this website to check it: Wolfram|Alpha
Originally Posted by maybnxtseasn f (x) = [x²+1]/[x²-1] i got f ''(x) = [12x²+4]/[(x²-1)^3] that's correct according to ... webMathematica Explorations: Step-by-Step Derivatives
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