integral (from 0 to infinite) of e^(-2x) / sqrt(x). i tried letting u = sqrt(x) so that x = u^2 and dx = 2u du and that turned my integral into 2 integral (from 0 to infinite) of e^(-2u^2) du. how would you do this integral? i checked wolfram alpha and it showed something about the error function but it didn't show the steps.
There is a mistake in my posting the first two integrals should be from to , then I want to leave it to the reader to divide by to get what you asked for. But changing the integral to be the first quadrant works as well (it shift where we divide by 2 to a different place but just as valid).
CB