you made a mistake, the integral is actually put and the remaining integral can be tackled by using trig. or hyperbolic substitution.
let f(x)=sinx fpr 0 to pi. Find the surface Area of the solid formed by revolving about the x-axis.
Now i know that it is the integral of 2pi Y ds which becomes 2pi sinx(1+(sinx)^2)^(1/2)
i just don't know how to integrate it after that. i tried a u sub and that didn't work. if someone could point me in the right direction that'd be great.