# limit

• March 6th 2010, 02:38 AM
Dgphru
limit
sorry im very dumb.. can someone please help me with this:

$
lim_{x-> 0}$
$\frac{sec^2x}{2}$
• March 6th 2010, 02:49 AM
Prove It
Quote:

Originally Posted by Dgphru
sorry im very dumb.. can someone please help me with this:

$
lim_{x-> 0}$
$\frac{sec^2x}{2}$

$\frac{\sec^2{x}}{2} = \frac{1}{2\cos^2{x}}$.

So $\lim_{x \to 0}\frac{\sec^2{x}}{2} = \lim_{x \to 0}\frac{1}{2\cos^2{x}}$

$= \frac{1}{2(\cos{0})^2}$

$= \frac{1}{2(1)^2}$

$= \frac{1}{2}$.