A particle moves along the so that at any time its accelaration is given by . At , the velocity of the particle is and its position is .
a) Find the velocity for .
b) Find the position for .
c) What is the position of the particle when it is farthest left?
I answered parts (a) and (b) (unsure if they're correct):
a)
b)
However I cannot answer part (c), here's what i have done(I have a bad feeling I am totally wrong):
Can anyone help?
Thanks in advance!
Is that "3" a typo? the integral of ln(t)- 2 is t ln(t)- 2t+ C. For x(1)= 4, you must have C= 6.
You find max and min of a function by setting the derivative equal to 0. Of course, here, the derivative is the speed. The particle will be farthest left when the speed was negative, becomes 0, and then becomes positive. When is ln(t)- 2= 0?However I cannot answer part (c), here's what i have done(I have a bad feeling I am totally wrong):
Can anyone help?
Thanks in advance!