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Math Help - [SOLVED] Limits... always doubting my answers

  1. #1
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    [SOLVED] Limits... always doubting my answers

    lim x -> 0
    1/x - 1/(x^2 + x)

    So I simplified this to 1 / x+1

    then I sub 0 into x and end up with 1/1.

    I have no confidence in myself when I do limits, I failed miserably on my mid term. How can I check if this is true?
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  2. #2
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    Quote Originally Posted by thekrown View Post
    lim x -> 0
    1/x - 1/(x^2 + x)

    So I simplified this to 1 / x+1

    then I sub 0 into x and end up with 1/1.

    I have no confidence in myself when I do limits, I failed miserably on my mid term. How can I check if this is true?
    You've done a good job here (although I'd have liked to see your working to know for sure that you got 1/(x + 1) by using correct algebra and not by accident). Your answer is correct.

    You can check it here: limit of 1/x - 1/(x^2 + x) as x approaches 0 - Wolfram|Alpha
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  3. #3
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    Well okay I began by putting everything on a common denominator and then and simplified.

    I got x+1-1 / x(x+1)

    or x / (x(x+1) and this is how I ended up with the answer.

    Thank you for your help.
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