it diverges, we can bound the general term as follows:
The problem asks whether this sum will converge or diverge:
What I had done from this point was to attempt to simplify the sum, by factoring the denominator so that instead of having:
So then back to the initial fraction, the factor of n would cancel and what would be left is:
Is it possible to simply take the limit of this or just even say that because the denominator is raised to a power of that the series must diverge? I am tempted to simply just note the power value and say that the sum must diverge then.
Thanks for the help, it's much appreciated.