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Math Help - Need help with one more derivative (quotient rule)

  1. #1
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    Need help with one more derivative (quotient rule)

    V= 1+x - 4 sq root x) / x

    I am confused as where to start on this problem. Do I use the quotient rule? Would I make the sq root of x.... x^1/2. Thanks for the help!
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  2. #2
    Member Miss's Avatar
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    Quote Originally Posted by KarlosK View Post
    V= 1+x - 4 sq root x) / x

    I am confused as where to start on this problem. Do I use the quotient rule? Would I make the sq root of x.... x^1/2. Thanks for the help!
    Is it \frac{1+x-4\sqrt{x}}{x} ?
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    Quote Originally Posted by Miss View Post
    Is it \frac{1+x-4\sqrt{x}}{x} ?
    Yes that is the problem! Sorry I don't know how to write it like that!
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  4. #4
    Member Miss's Avatar
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    Quote Originally Posted by KarlosK View Post
    Yes that is the problem! Sorry I don't know how to write it like that!
    Recall that : \frac{a+b+c}{d}=\frac{a}{d}+\frac{b}{d}+\frac{c}{d  } \, for d \neq 0.
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    Quote Originally Posted by Miss View Post
    Recall that : \frac{a+b+c}{d}=\frac{a}{d}+\frac{b}{d}+\frac{c}{d  } \, for d \neq 0.
    So would I just set this up as

    1/x + x/x -4/x x^1/2 /x?? And then find the derivative of that?
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  6. #6
    Member Miss's Avatar
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    Quote Originally Posted by KarlosK View Post
    So would I just set this up as

    1/x + x/x -4/x x^1/2 /x?? And then find the derivative of that?
    Please, use brackets to make your post readable.

    1/x+x/x could be (1/x)+(x/x) or ( (1/x) + x ) / x ... etc
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