V= 1+x - 4 sq root x) / x I am confused as where to start on this problem. Do I use the quotient rule? Would I make the sq root of x.... x^1/2. Thanks for the help!
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Originally Posted by KarlosK V= 1+x - 4 sq root x) / x I am confused as where to start on this problem. Do I use the quotient rule? Would I make the sq root of x.... x^1/2. Thanks for the help! Is it $\displaystyle \frac{1+x-4\sqrt{x}}{x}$ ?
Originally Posted by Miss Is it $\displaystyle \frac{1+x-4\sqrt{x}}{x}$ ? Yes that is the problem! Sorry I don't know how to write it like that!
Originally Posted by KarlosK Yes that is the problem! Sorry I don't know how to write it like that! Recall that : $\displaystyle \frac{a+b+c}{d}=\frac{a}{d}+\frac{b}{d}+\frac{c}{d } \, $ for $\displaystyle d \neq 0$.
Originally Posted by Miss Recall that : $\displaystyle \frac{a+b+c}{d}=\frac{a}{d}+\frac{b}{d}+\frac{c}{d } \, $ for $\displaystyle d \neq 0$. So would I just set this up as 1/x + x/x -4/x x^1/2 /x?? And then find the derivative of that?
Originally Posted by KarlosK So would I just set this up as 1/x + x/x -4/x x^1/2 /x?? And then find the derivative of that? Please, use brackets to make your post readable. 1/x+x/x could be (1/x)+(x/x) or ( (1/x) + x ) / x ... etc
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