# Thread: Need help with one more derivative (quotient rule)

1. ## Need help with one more derivative (quotient rule)

V= 1+x - 4 sq root x) / x

I am confused as where to start on this problem. Do I use the quotient rule? Would I make the sq root of x.... x^1/2. Thanks for the help!

2. Originally Posted by KarlosK
V= 1+x - 4 sq root x) / x

I am confused as where to start on this problem. Do I use the quotient rule? Would I make the sq root of x.... x^1/2. Thanks for the help!
Is it $\frac{1+x-4\sqrt{x}}{x}$ ?

3. Originally Posted by Miss
Is it $\frac{1+x-4\sqrt{x}}{x}$ ?
Yes that is the problem! Sorry I don't know how to write it like that!

4. Originally Posted by KarlosK
Yes that is the problem! Sorry I don't know how to write it like that!
Recall that : $\frac{a+b+c}{d}=\frac{a}{d}+\frac{b}{d}+\frac{c}{d } \,$ for $d \neq 0$.

5. Originally Posted by Miss
Recall that : $\frac{a+b+c}{d}=\frac{a}{d}+\frac{b}{d}+\frac{c}{d } \,$ for $d \neq 0$.
So would I just set this up as

1/x + x/x -4/x x^1/2 /x?? And then find the derivative of that?

6. Originally Posted by KarlosK
So would I just set this up as

1/x + x/x -4/x x^1/2 /x?? And then find the derivative of that?