Thread: Derivatives: Product/Quotient Rule

I am working on this problem.

V=(1-t) (1+t^2)^-1

The ^-1 is what is confusing me.

I set it up like this.

(1-t)(2t) + (1+t^2)(-1) I don't think this is right because I did not account for the ^-1. Does that mean I would make the (2t^-1) making it -2t??

Originally Posted by KarlosK

I am working on this problem.

V=(1-t) (1+t^2)^-1

The ^-1 is what is confusing me.

I set it up like this.

(1-t)(2t) + (1+t^2)(-1) I don't think this is right because I did not account for the ^-1. Does that mean I would make the (2t^-1) making it -2t??

$\displaystyle (1-t)(t^2+1)^{-1} = \frac{1-t}{t^2+1}$

Originally Posted by Miss

$\displaystyle (1-t)(t^2+1)^{-1} = \frac{1-t}{t^2+1}$

I always forget that stupid rule!! Let me try to work through the rest of this and I will post what I get thank you!