Are you trying to integrate [-1/(2-3x)] dx?

If so, you CANNOT take 1/3 outside the integration symbol.

Use Substution here:

Suppose that u = 2-3x

Then, du = -3 dx

so, dx = -du/3

substitute this value of dx in the question and you get,

Integral of [-1/u] -du/3

= Integration of 1/3 [1/u] du

= 1/3* ln(u) +c

substitute u = 2-3x, and you have

1/3 * ln(2-3x) + c

which is your answer...

DO not forget to substitute in this case