Hi everyone - very quick one here

Ill usefin bold do denote integration symbol because I havn't fully mastered the thing to enter formulae yet

Anyway I'm looking to integrate [(-1)/(2-3x)]

is it right to take 1/3 outside the integration symbol to give:

or should it be:+1/3f[(-1)/(2/3 -x)]

(1/3) ln |(2/3)-x| + c

The answers gives the bottom one but I got the top one - am I wrong? why?+1/3f[(-3)/(2-3x)

(1/3) ln |2-3x| +c

Thanks