# Please help! I kinda have the answer but Im not sure if its right

• March 4th 2010, 11:33 AM
Jluse7
Please help! I kinda have the answer but Im not sure if its right
For x3y2+y3x=-6, find dy/dx. I get an answer that is close to the right answer, but either my y is off by an exponent or something.
• March 4th 2010, 11:48 AM
JoshMH91
What answer do you get ?
• March 4th 2010, 11:58 AM
Jluse7
-3x2y2-y3 / 3x2y+y3
• March 4th 2010, 12:24 PM
elim
Re: Please help! I kinda have the answer but Im not sure if its right
$x^3y^2+y^3x=-6$

$3x^2y^2+2x^3y y' +y^3+3xy^2 y'=0$

$\frac{dy}{dx} = -\frac{3x^2y+ y^2}{2x^3+3xy}$
• March 4th 2010, 12:27 PM
Jluse7
Okay but why didnt you make it like -3x2y2-y3 / 2x3y+3xy2
• March 4th 2010, 06:37 PM
elim
Re.why
when numerator and denominator have common factor, we can simplify the quotient.