• March 4th 2010, 11:33 AM
Jluse7
For x3y2+y3x=-6, find dy/dx. I get an answer that is close to the right answer, but either my y is off by an exponent or something.
• March 4th 2010, 11:48 AM
JoshMH91
What answer do you get ?
• March 4th 2010, 11:58 AM
Jluse7
-3x2y2-y3 / 3x2y+y3
• March 4th 2010, 12:24 PM
elim
$x^3y^2+y^3x=-6$
$3x^2y^2+2x^3y y' +y^3+3xy^2 y'=0$
$\frac{dy}{dx} = -\frac{3x^2y+ y^2}{2x^3+3xy}$