For x3y2+y3x=-6, find dy/dx. I get an answer that is close to the right answer, but either my y is off by an exponent or something.

- Mar 4th 2010, 11:33 AMJluse7Please help! I kinda have the answer but Im not sure if its right
For x3y2+y3x=-6, find dy/dx. I get an answer that is close to the right answer, but either my y is off by an exponent or something.

- Mar 4th 2010, 11:48 AMJoshMH91
What answer do you get ?

- Mar 4th 2010, 11:58 AMJluse7
-3x2y2-y3 / 3x2y+y3

- Mar 4th 2010, 12:24 PMelimRe: Please help! I kinda have the answer but Im not sure if its right
$\displaystyle x^3y^2+y^3x=-6$

$\displaystyle 3x^2y^2+2x^3y y' +y^3+3xy^2 y'=0$

$\displaystyle \frac{dy}{dx} = -\frac{3x^2y+ y^2}{2x^3+3xy}$ - Mar 4th 2010, 12:27 PMJluse7
Okay but why didnt you make it like -3x2y2-y3 / 2x3y+3xy2

- Mar 4th 2010, 06:37 PMelimRe.why
when numerator and denominator have common factor, we can simplify the quotient.