Originally Posted by

**dojo** I'm struggling with this question - I think I'm ok with the calculus its just the maniplutaion. Anyway, your help and guidence would be very much appreciated.

The equ. of a curve is (6y^2) = (e^x)(y^3) - 2e^4x.

Given that (a,b) is the point on the curve at which dy/dx = 0,

show that b = 2e^a

By substituting into the equ. obtain a further relationship between a and b, and hence find the values of a and b.

OK

So by implicit diff. and rearranging

(e^x(y^3 - (8e^3x)) / 3y(4 - (e^x)y)) = 0