$\displaystyle \int x^2(1+x^2)^2dx$ Do I have to use by parts here or can I expand the brackets and get: $\displaystyle x^8/8+2x^6/6+x^4/4+c$ Thanks in advance!!!
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Originally Posted by NFZ17 $\displaystyle \int x^2(1+x^2)^2dx$ Do I have to use by parts here or can I expand the brackets and get: $\displaystyle x^8/8+2x^6/6+x^4/4+c$ Thanks in advance!!! Simplest is to expand the brackets, but you should then have $\displaystyle \int{\left(x^2+2x^4+x^6\right)}dx$
Thanks, I came up with $\displaystyle x^7/7+2x^5/5+x^3/3+c$ My original answer was for $\displaystyle \int x^3 (1+x^2 )^2 dx$ not $\displaystyle \int x^2 (1+x^2 )^2 dx$ Sorry for the mix up! Thanks again
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