$\displaystyle \int x^2(1+x^2)^2dx$

Do I have to use by parts here or can I expand the brackets and get:

$\displaystyle x^8/8+2x^6/6+x^4/4+c$

Thanks in advance!!!

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- Mar 4th 2010, 05:02 AMNFZ17Do I have to use By Parts?
$\displaystyle \int x^2(1+x^2)^2dx$

Do I have to use by parts here or can I expand the brackets and get:

$\displaystyle x^8/8+2x^6/6+x^4/4+c$

Thanks in advance!!! - Mar 4th 2010, 05:24 AMArchie Meade
- Mar 4th 2010, 05:59 AMNFZ17
Thanks,

I came up with

$\displaystyle x^7/7+2x^5/5+x^3/3+c$

My original answer was for

$\displaystyle \int x^3 (1+x^2 )^2 dx$

not

$\displaystyle \int x^2 (1+x^2 )^2 dx$

Sorry for the mix up!

Thanks again