Question:
6a)
Calculate the area bounded by the parabola, y=8-x^2 and y=x^2.
I don't know how to attempt and I don't know how to find the x intercepts.
Answer:
21/1/3.
Thanks.
Hi AwsomGuy,
you are looking for the area between the 2 curves.
$\displaystyle y=8-x^2$
is a parabola with a maximum at the point (0,8).
$\displaystyle y=x^2$
is a parabola with a minimum at (0,0).
First find the point of intersection
$\displaystyle 8-x^2=x^2\ \Rightarrow\ 8=2x^2\ \Rightarrow\ x^2=4\ \Rightarrow x=\pm2$
$\displaystyle x=\pm2,\ y=4$
Now integrate $\displaystyle \left(8-x^2\right)-\left(x^2\right)$
from x=-2 to x=2