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Math Help - [SOLVED] Area of a Curve

  1. #1
    Member Awsom Guy's Avatar
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    [SOLVED] Area of a Curve

    Question:
    6a)
    Calculate the area bounded by the parabola, y=8-x^2 and y=x^2.

    I don't know how to attempt and I don't know how to find the x intercepts.
    Answer:
    21/1/3.

    Thanks.
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  2. #2
    Member Awsom Guy's Avatar
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    Any help?
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  3. #3
    Member Awsom Guy's Avatar
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    Is the x intercepts +/- 2.8.
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  4. #4
    Member Awsom Guy's Avatar
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    thanks guys got the answer lols.... sad no help at all....
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  5. #5
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    The user below got there before me.

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    Last edited by Gojinn; March 4th 2010 at 03:05 AM.
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  6. #6
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    Quote Originally Posted by Awsom Guy View Post
    Question:
    6a)
    Calculate the area bounded by the parabola, y=8-x^2 and y=x^2.

    I don't know how to attempt and I don't know how to find the x intercepts.
    Answer:
    21/1/3.

    Thanks.
    Hi AwsomGuy,

    you are looking for the area between the 2 curves.

    y=8-x^2

    is a parabola with a maximum at the point (0,8).

    y=x^2

    is a parabola with a minimum at (0,0).

    First find the point of intersection

    8-x^2=x^2\ \Rightarrow\ 8=2x^2\ \Rightarrow\ x^2=4\ \Rightarrow x=\pm2

    x=\pm2,\ y=4

    Now integrate \left(8-x^2\right)-\left(x^2\right)

    from x=-2 to x=2
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