# Thread: [SOLVED] Area of a Curve

1. ## [SOLVED] Area of a Curve

Question:
6a)
Calculate the area bounded by the parabola, y=8-x^2 and y=x^2.

I don't know how to attempt and I don't know how to find the x intercepts.
21/1/3.

Thanks.

2. Any help?

3. Is the x intercepts +/- 2.8.

4. thanks guys got the answer lols.... sad no help at all....

5. The user below got there before me.

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6. Originally Posted by Awsom Guy
Question:
6a)
Calculate the area bounded by the parabola, y=8-x^2 and y=x^2.

I don't know how to attempt and I don't know how to find the x intercepts.
21/1/3.

Thanks.
Hi AwsomGuy,

you are looking for the area between the 2 curves.

$\displaystyle y=8-x^2$

is a parabola with a maximum at the point (0,8).

$\displaystyle y=x^2$

is a parabola with a minimum at (0,0).

First find the point of intersection

$\displaystyle 8-x^2=x^2\ \Rightarrow\ 8=2x^2\ \Rightarrow\ x^2=4\ \Rightarrow x=\pm2$

$\displaystyle x=\pm2,\ y=4$

Now integrate $\displaystyle \left(8-x^2\right)-\left(x^2\right)$

from x=-2 to x=2