# [SOLVED] Area of a Curve

• Mar 4th 2010, 01:25 AM
Awsom Guy
[SOLVED] Area of a Curve
Question:
6a)
Calculate the area bounded by the parabola, y=8-x^2 and y=x^2.

I don't know how to attempt and I don't know how to find the x intercepts.
21/1/3.

Thanks.
• Mar 4th 2010, 01:36 AM
Awsom Guy
Any help?
• Mar 4th 2010, 01:39 AM
Awsom Guy
Is the x intercepts +/- 2.8.
• Mar 4th 2010, 02:20 AM
Awsom Guy
thanks guys got the answer lols.... :( sad no help at all....
• Mar 4th 2010, 02:50 AM
Gojinn
The user below got there before me. :p

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• Mar 4th 2010, 03:01 AM
Quote:

Originally Posted by Awsom Guy
Question:
6a)
Calculate the area bounded by the parabola, y=8-x^2 and y=x^2.

I don't know how to attempt and I don't know how to find the x intercepts.
21/1/3.

Thanks.

Hi AwsomGuy,

you are looking for the area between the 2 curves.

$y=8-x^2$

is a parabola with a maximum at the point (0,8).

$y=x^2$

is a parabola with a minimum at (0,0).

First find the point of intersection

$8-x^2=x^2\ \Rightarrow\ 8=2x^2\ \Rightarrow\ x^2=4\ \Rightarrow x=\pm2$

$x=\pm2,\ y=4$

Now integrate $\left(8-x^2\right)-\left(x^2\right)$

from x=-2 to x=2