If you could help me figure this integral out I would be very grateful.
top limit: 6
bottom limit: 4
of dx / (x-3)sqrt(x^2-6x+8)
The question involves the arc graphs and whatnot. I'm just really confused.
Sorry if this is a little messy, I'm not experienced with latex. any help would be appreciated, thanks.
Im not even sure where to begin. I know i must make a u substitution but I dont know what with.
So the integral actually becomes:
Now since that means .
I suggest you consult your tables of integrals to evaluate this integral.
For an alternative method,
integral[1/((x - 3)*Sqrt[(x - 3)^2 - 1])] - Wolfram|Alpha
Click "Show Steps".