I need to find the surface area of the above curve, about the x-axis. I'm having trouble taking the integral. Once everthing is set up its: from 4 to 9 Or at least, that's what I think it is.. Any help would be greatly appreciated.
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Originally Posted by cdlegendary I need to find the surface area of the above curve, about the x-axis. I'm having trouble taking the integral. Once everthing is set up its: from 4 to 9 Or at least, that's what I think it is.. Any help would be greatly appreciated. As you know, the surface area of a revolution is found through the following formula: Your integral is correct except for the term, just need to recheck the square.
Last edited by Kasper; March 3rd 2010 at 09:23 PM.
Ah, I made a typo. so the integral would be: since the derivative of is is it not?
Originally Posted by cdlegendary Ah, I made a typo. so the integral would be: since the derivative of is is it not? You bet.
thanks, I'm still having trouble taking the integral though. any pointers?
How about that ? --Kevin C.
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