# Math Help - Integration problem with trigonometry

1. ## Integration problem with trigonometry

Hi, I'm having trouble figuring out how to get the answer to this integral. I understand why the answer is what it is, but I don't know how to get there.

$\int cot^2x csc^2x dx$

$= -\frac{1}{3} cot^3 x + C$

Thank you

2. Originally Posted by cynlix
Hi, I'm having trouble figuring out how to get the answer to this integral. I understand why the answer is what it is, but I don't know how to get there.

$\int cot^2x csc^2x dx$

$= -\frac{1}{3} cot^3 x + C$

Thank you
Try substituting $u=cotx$.