Hi, I'm having trouble figuring out how to get the answer to this integral. I understand why the answer is what it is, but I don't know how to get there.
$\displaystyle \int cot^2x csc^2x dx$
$\displaystyle = -\frac{1}{3} cot^3 x + C$
Thank you
Hi, I'm having trouble figuring out how to get the answer to this integral. I understand why the answer is what it is, but I don't know how to get there.
$\displaystyle \int cot^2x csc^2x dx$
$\displaystyle = -\frac{1}{3} cot^3 x + C$
Thank you