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    Minimum 2

    What is the radius of a cylindrical soda can with volume of 512 cubic inches that will use the minimum material?
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    Quote Originally Posted by deltaX View Post
    What is the radius of a cylindrical soda can with volume of 512 cubic inches that will use the minimum material?
    512 = \pi r^2 h

    h = \frac{512}{\pi r^2}

    material required = total surface area of the cylinder ...

    A = 2\pi r^2 + 2\pi rh

    sub in the expression for h given above to get A in terms of r only ...

    find \frac{dA}{dr} and minimize
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