Hi,

My problem is: Find the area of the surface obtained by rotating the curve $\displaystyle x = 5 e^{2y} $ from y=0 to y = 2 about the y-axis.

I use the surface Formula: $\displaystyle S = \int_a^b {2 \pi x} \sqrt{1+{x'}^2} dy $

but could do no more after plug in $\displaystyle {x'} = 10e^y $

Could anyone help me with this? THANKS!!