I got it. The formula is y=mx+b
In this case,
y=-50x+b
-122=-50(5)+b
-122=-250+b
-122+250=b
128=b
y=-50x+128
I'm struggling with the following. I have a question such as:
Find an equation for the line tangent to at (5,-122)
I know how to calculate the slope which is:
And the above in slope intercept form is:
How was the slope intercept form calculated? I can't seem to figure this out.