Thread: finding absolute extrema

normal equation
----------------
f(x) = (2x+5)/3 , [0,5] <--- interval

used quotient rule and obtained 2/3 as the derivative....

this means the slope of the function f(x) is constant slope of 2/3....

im guessing the max point is x=5 and min is x=0?

Originally Posted by maybnxtseasn

normal equation
----------------
f(x) = (2x+5)/3 , [0,5] <--- interval

used quotient rule and obtained 2/3 as the derivative....

this means the slope of the function f(x) is constant slope of 2/3....

im guessing the max point is x=5 and min is x=0?

Correct.
Actually, the general function is just a straight line, if then the line is increasing, so the maximum value occurs at the bigger end point and vice versa.