f(x,y,z)=x+2y Constraints y^2+z^2=1 x+y+z=3 Find Max and Min
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Originally Posted by UODuck1879 f(x,y,z)=x+2y Constraints y^2+z^2=1 x+y+z=3 Find Max and Min From the second constraint, x+y = 3-z f(x,y,z) = x+2y = y + (3-z) = 3 + (y-z) So, on the circle y^2+z^2=1, where is y-z greatest? smallest? Post again if you're still having trouble.
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