$\displaystyle \lim_{x \to \infty} \frac{\sqrt{x+5}}{\sqrt{x}+5} $ $\displaystyle \lim_{x \to \infty} \frac{2x}{x+7\sqrt{x}} $ I can't find a way around it because L'hopital's rule doesnt work
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Originally Posted by larryboi7 $\displaystyle \lim_{x \to \infty} \frac{\sqrt{x+5}}{\sqrt{x}+5} $ $\displaystyle \lim_{x \to \infty} \frac{2x}{x+7\sqrt{x}} $ I can't find a way around it because L'hopital's rule doesnt work Why it does not work? For the first devide top and bottom by $\displaystyle \sqrt{x}$. For the second devide top and bottom by $\displaystyle x$.
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