...A searchlight is located at point A, 40 feet from a wall. The searchlight revolves counterclockwise at a rate of pi/30 radians per second. at any point B on the wall, the strength of the light L, is inversely proportional to the square of the distance d frm A; that is, at any point on the wall L=k/d^2. At the closest point P, L=10,000 Lumens
A) Find the constant of proportionality k.
... solve for k
B) express L as a function of thetak the angle formed by AP and AB
solve for d in terms of , then determine L as a function of
C) how fast(in lumens per second) is the strength of the light changing when theta=pi/4? Is it increasing or decreasing? Justify your answer.
determine the value of at the stated angle.
D) Find the value of theta between theta=0 and theta=pi/2 after which L is less than 1000 lumens
set the expression for L < 1000 and solve for