So I'm confused on how to take the first integral because of the radical... please explain how you came to your answer. (S=integral, so S:0,1 means the integral from 0 to 1, just to explain my notation)

S:0,1(S:0,1 dy)dx

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- Mar 2nd 2010, 07:58 AMRhode963Find the double integral
So I'm confused on how to take the first integral because of the radical... please explain how you came to your answer. (S=integral, so S:0,1 means the integral from 0 to 1, just to explain my notation)

S:0,1(S:0,1 dy)dx - Mar 2nd 2010, 08:15 AMTheEmptySet
- Mar 2nd 2010, 08:18 AMRhode963
Great help, but it is actually the double integral of from 0 to 1. Sorry, I don't know how to get the integral symbol to work.

- Mar 2nd 2010, 08:29 AMRhode963
Would u-sub still work? So for the inner integral I could pull out an x, and get x times the integral of ?

- Mar 2nd 2010, 08:31 AMTheEmptySet
- Mar 2nd 2010, 08:35 AMRhode963
So for the inside integral, I got the answer to be , does that sound right to you? It seems like a strange amount of canceling. And when plugging into the final integral, I got the final answer to be 3.

- Mar 2nd 2010, 01:09 PMGeneral