Hello,

I've attached an image of the grapghs and the enclosed area.

First calculate the intersections of the 2 graphs:

x³ + 3x² + 2x = 2x² + 4x ===> x³ + x² - 2x = 0 The LHS can be factorized:

x³ + x² - 2x = x(x + 2)(x - 1)

To calculate the enclosed area you use the difference of the 2 functions:

d(x) = x³ + x² - 2x

A = |∫[from -2 to 0](x³ + x² - 2x)dx| + |∫[from 0 to 1](x³ + x² - 2x)dx|

A = |[from -2 to 0](¼ x^4 + (1/3)x³ - x²)dx| + |[from 0 to 1](¼ x^4 + (1/3)x³ - x²)dx|

A = |0 - (-8/3)| + |(-5/12) - 0| = 37/12

EB