Thread: Finding the are of the curve

Find length of the curve
y=ln(cosx) {x,0,pi/2}

I am stuck and I dont know how to integrate sqrt(sec^2).

My Work:

Originally Posted by racewithferrari

Find length of the curve
y=ln(cosx) {x,0,pi/2}

I am stuck and I dont know how to integrate sqrt(sec^2).

My Work:

since the limits of integration are in quad I, you can drop the absolute value.

further, note that ...

I do not get it about dropping the absolute value.
I know what the integral of sqrt(sec^2) is . But I know dont know how I will solve it comes to Exams.

you say this in your original post ...

I am stuck and I dont know how to integrate sqrt(sec^2).

then you say this in a subsequent post ...

I know what the integral of sqrt(sec^2) is. But I know dont know how I will solve it comes to Exams.

pardon me if I do not understand your difficulty.

here is the arclength calculation ...