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Math Help - implicit differentiation

  1. #1
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    implicit differentiation

    how do i find dy/dx? where y = cos (xy^2) could i say dy/dx = -sin (xy^2) times the derivative of the inside stuff? with respect to x. i suppose i would use the product rule? right or is there an easier way to do this problem?
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  2. #2
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    Hello, slapmaxwell1!

    How do i find \frac{dy}{dx}\,\text{ where }\,y \:=\: \cos(xy^2)

    Could i say: . \frac{dy}{dx} \:=\: -\sin(xy^2) .times the derivative of the inside stuff with respect to x? . Yes!

    i suppose i would use the product rule, right? . Right!

    or is there an easier way to do this problem? . I don't think so.

    You'd have: . \frac{dy}{dx} \;=\;-\sin(xy^2)\cdot\bigg[x\cdot2y\frac{dy}{dx} + y^2\bigg]

    Then solve for \frac{dy}{dx} . . . carefully.

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  3. #3
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    i will definitely take my time, thanks again, once i finish this problem i get to review washers and disc's?? looks i will be here tonight. lol
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