does anyone know how to find the integral of: e^(x^2)
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Originally Posted by cdlegendary does anyone know how to find the integral of: e^(x^2) the antiderivative of $\displaystyle \int e^{x^2} \, dx$ does not have an elementary, closed-form solution.
Originally Posted by skeeter the antiderivative of $\displaystyle \int e^{x^2} \, dx$ does not have an elementary, closed-form solution. ah, so if the interval is from 0 to 1, would there be a solution?
Originally Posted by cdlegendary ah, so if the interval is from 0 to 1, would there be a solution? no, but you can estimate the value of the definite integral using the series representation for $\displaystyle e^u$
Its not an elementary function as skeeter said. You can do it as an infinite series. Since: $\displaystyle e^{\left(x^2\right)}=\sum_{n=0}^{\infty} \frac{x^{2n}}{n!}$.
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