find the parametric eqn for the line lying on the plane x+y+z=3 and intersecting the line x=2+t , y=1-t, z=-3t perpendicularly.

I found the point of intersection to be (2,1,0).

how do i get the other point? I was thinking that if the plane would intersect the line perpendicularly, wouldnt any other point on that plane, that satisfies x+y+z = 3 be enough to form the parametric eqn that i need?

eg. B (1,1,1)? or (0,0,3). is there a unique solution?