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Math Help - Confused over Tangent Line: I'm right, but it I'm told otherwise.

  1. #1
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    Confused over Tangent Line: I'm right, but it I'm told otherwise.

    The Image speaks for it's self.
    Attached Thumbnails Attached Thumbnails Confused over Tangent Line: I'm right, but it I'm told otherwise.-tangent-line.jpg  
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  2. #2
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    Quote Originally Posted by Zanderist View Post
    The Image speaks for it's self.
    Point gradient formula is y - y0 = m(x-x0)

     y - 3 = 6 \cos \frac{\pi}{6} \left(x - \frac{\pi}{6} \right)

    For the constant b:

      6 \cos \left( \frac{\pi}{6} \right)\times \frac{-\pi}{6} + 3 = - \not6 \left( \frac{\sqrt 3}{2} \right) \times \frac{\pi}{\not6} + 3 = \frac{\sqrt 3}{2} \pi + 3
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  3. #3
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    Quote Originally Posted by Gusbob View Post
    Point gradient formula is y - y0 = m(x-x0)

     y - 3 = 6 \cos \frac{\pi}{6} \left(x - \frac{\pi}{6} \right)

    For the constant b:

      6 \cos \left( \frac{\pi}{6} \right)\times \frac{-\pi}{6} + 3 = - \not6 \left( \frac{\sqrt 3}{2} \right) \times \frac{\pi}{\not6} + 3 = \frac{\sqrt 3}{2} \pi + 3


    just integrate the function 6sin(x). you get 6 cosine(x). Y = mx +b where your equation is y = 6 cos (x) and your points are pi/6,3.
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  4. #4
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    Quote Originally Posted by ThorAsgard View Post
    just integrate the function 6sin(x). you get 6 cosine(x). Y = mx +b where your equation is y = 6 cos (x) and your points are pi/6,3.
    I think you mean just take the derivative. The integral of 6sin(x) is -6cos(x). But you put the right answer, 6cos(x) so I assume you just used the wrong word. Right math, wrong word =)
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