# Thread: Confused over Tangent Line: I'm right, but it I'm told otherwise.

1. ## Confused over Tangent Line: I'm right, but it I'm told otherwise.

The Image speaks for it's self.

2. Originally Posted by Zanderist
The Image speaks for it's self.
Point gradient formula is y - y0 = m(x-x0)

$y - 3 = 6 \cos \frac{\pi}{6} \left(x - \frac{\pi}{6} \right)$

For the constant b:

$6 \cos \left( \frac{\pi}{6} \right)\times \frac{-\pi}{6} + 3 = - \not6 \left( \frac{\sqrt 3}{2} \right) \times \frac{\pi}{\not6} + 3 = \frac{\sqrt 3}{2} \pi + 3$

3. Originally Posted by Gusbob
Point gradient formula is y - y0 = m(x-x0)

$y - 3 = 6 \cos \frac{\pi}{6} \left(x - \frac{\pi}{6} \right)$

For the constant b:

$6 \cos \left( \frac{\pi}{6} \right)\times \frac{-\pi}{6} + 3 = - \not6 \left( \frac{\sqrt 3}{2} \right) \times \frac{\pi}{\not6} + 3 = \frac{\sqrt 3}{2} \pi + 3$

just integrate the function 6sin(x). you get 6 cosine(x). Y = mx +b where your equation is y = 6 cos (x) and your points are pi/6,3.

4. Originally Posted by ThorAsgard
just integrate the function 6sin(x). you get 6 cosine(x). Y = mx +b where your equation is y = 6 cos (x) and your points are pi/6,3.
I think you mean just take the derivative. The integral of 6sin(x) is -6cos(x). But you put the right answer, 6cos(x) so I assume you just used the wrong word. Right math, wrong word =)