problem 1 on Flickr - Photo Sharing! Help? How do I do this one? The answer I get isn't an option. Thank you very much
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Hello, Excause me, can you show your work? Maybe your solution is correct. But the another answer is the same but in different form.
Basically I used the quotient rule and got (1+y')(x-y)-(1-y')(x+y) / (x-y)^2 I simplified it to -2y+2y'x/(x-y)^2 = 2x +2yy' then I kinda stopped because I noticed that my answer was not going to match the ones given. Anyways thank you for responding.
Originally Posted by bananasinpajamas Basically I used the quotient rule and got (1+y')(x-y)-(1-y')(x+y) / (x-y)^2 I simplified it to -2y+2y'x/(x-y)^2 = 2x +2yy' then I kinda stopped because I noticed that my answer was not going to match the ones given. Anyways thank you for responding. Well, now solve it for $\displaystyle y'$. The question wants you to find $\displaystyle y'=\frac{dy}{dx}$.
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