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Math Help - Definite integrals help again

  1. #1
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    Unhappy Definite integrals help again

    Hint: Divide the numerator by the denominator

    Answer key at book:
    6215/12
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  2. #2
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    Quote Originally Posted by ^_^Engineer_Adam^_^ View Post
    Hint: Divide the numerator by the denominator

    Answer key at book:
    6215/12
    Hello,

    honestly I don't understand your hint

    ∫(√(t) - 1/√(t) + t^(1/3))dt = ∫[from 1 to 64](t^(1/2))dt - ∫(t^(-1/2))dt + ∫(t^(1/3))dt =

    [from 1 to 64]((2/3)t^(3/2) - 2*t^(1/2) + (3/4)*t^(4/3))

    Now plug in the known values:

    [from 1 to 64]((2/3)t^(3/2) - 2*t^(1/2) + (3/4)*t^(4/3)) = (1552/3) - (-7/12) = 6215/12

    EB
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