Hi, what is the integral of $\displaystyle 1/x^2 $
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Originally Posted by wolfhound Hi, what is the integral of $\displaystyle 1/x^2 $ $\displaystyle \int \frac{1}{x^2} \, dx = \int x^{-2} \, dx$ use the power rule for antiderivatives ... what do you get?
$\displaystyle 1/x $ ?
Originally Posted by wolfhound $\displaystyle 1/x $ ? not quite ... $\displaystyle -\frac{1}{x} + C$
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