given is F(x)= the integral from x=1 to x=2x^3 of the function (3t-4)^2 dt
I need to find the equation of the tangent line to F(x) at x=-1
so far i have:
f=600 (which is the slope of F at x=-1)
i need help finding the (x,y) coordinates
given is F(x)= the integral from x=1 to x=2x^3 of the function (3t-4)^2 dt
I need to find the equation of the tangent line to F(x) at x=-1
so far i have:
f=600 (which is the slope of F at x=-1)
i need help finding the (x,y) coordinates