given is F(x)= the integral from x=1 to x=2x^3 of the function (3t-4)^2 dt I need to find the equation of the tangent line to F(x) at x=-1 so far i have: f=600 (which is the slope of F at x=-1) i need help finding the (x,y) coordinates
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Originally Posted by gamefreeze given is F(x)= the integral from x=1 to x=2x^3 of the function (3t-4)^2 dt I need to find the equation of the tangent line to F(x) at x=-1 so far i have: f=600 (which is the slope of F at x=-1) i need help finding the (x,y) coordinates Let Ok, In get the same thing there. Think of the equation of the tangent line as follows: So you need to find So that's just a basic definite integral right? So just evaluate F(-1) by using the substitution rule.
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