Thread: Squeeze Theorem (can't find upper bound)

I need to use the Squeeze Theorem to show that
as n => infinity (3^n / n!) => 0

for a lower bound I can use (1^n / n!) which is always smaller and => 0

I cannot think of a suitable upper bound function where the limit is 0 and can easily be shown though.

Originally Posted by crymorenoobs

I need to use the Squeeze Theorem to show that
as n => infinity (3^n / n!) => 0

for a lower bound I can use (1^n / n!) which is always smaller and => 0

I cannot think of a suitable upper bound function where the limit is 0 and can easily be shown though.

3^n < (n-1)! for n > 8.

Ok thanks.