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Math Help - Squeeze Theorem (can't find upper bound)

  1. #1
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    Squeeze Theorem (can't find upper bound)

    I need to use the Squeeze Theorem to show that
    as n => infinity (3^n / n!) => 0

    for a lower bound I can use (1^n / n!) which is always smaller and => 0

    I cannot think of a suitable upper bound function where the limit is 0 and can easily be shown though.
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  2. #2
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    Quote Originally Posted by crymorenoobs View Post
    I need to use the Squeeze Theorem to show that
    as n => infinity (3^n / n!) => 0

    for a lower bound I can use (1^n / n!) which is always smaller and => 0

    I cannot think of a suitable upper bound function where the limit is 0 and can easily be shown though.
    3^n < (n-1)! for n > 8.
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  3. #3
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    Ok thanks.
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