sin(theta)=opp/adjA Weather Balloon that is rising vertically is being observed from a point on the ground 2 miles from the spot directly beneath the balloon. At what rate is the balloon rising when the angle between the ground and the observer's line of sight is pi/5 and is increasing at 0.2 radians per minute?
x = theta
h = height of balloon
dx/dt = ?
dh/dt = .2 radians per minute
im doing related rates in my calc class now too and i think this is how you can do this problem.hope i helped