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Math Help - other Functions problems help?

  1. #1
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    other Functions problems help?

    Statement:
    A company advertises on Radio and TV for its product. the profit based on these advertisement has been
    determine in 1000 is as P(x,y)=-2x^2-xy-y^2+8x+9y+10
    where x is the amount spent on Radio and y is the amount spend on TV respectively. How much money should
    be spent on both advertisement to maximize the profit? another

    Friends I CANT SOLVE it just give me method

    Please friends this time help me!

    thanks a lot
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  2. #2
    Member Mauritzvdworm's Avatar
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    you need to take the partial derivatives of P with respect to both x and y

    then in order to find the max equate them to zero, you will then have two equations together with two unknown terms, solve.

    you should get two solutions in this case, just test which one will give you the max.
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  3. #3
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    Quote Originally Posted by Mauritzvdworm View Post

    you should get two solutions in this case, just test which one will give you the max.
    define it please
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  4. #4
    Member Mauritzvdworm's Avatar
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    \frac{\partial P}{\partial x}=-4x-y+8 and
    \frac{\partial P}{\partial y}=-x-2y+9

    now equate them to zero
    -4x-y+8=0 so y=-4x+8 and
    -x-2y+9=0 so

    -x-2(-4x+8)+9=0 so x=1 and y=4

    so you end up with the coordinate (1,4) and if you test it it should give you the maximum.
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  5. #5
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    Quote Originally Posted by Mauritzvdworm View Post
    \frac{\partial P}{\partial x}=-4x-y+8 and
    \frac{\partial P}{\partial y}=-x-2y+9

    now equate them to zero
    -4x-y+8=0 so y=-4x+8 and
    -x-2y+9=0 so

    -x-2(-4x+8)+9=0 so x=1 and y=4

    so you end up with the coordinate (1,4) and if you test it it should give you the maximum.


    thanks man
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  6. #6
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    Well, your original post mislead us. You said, highlighted in red, "just give me the method:" That is what Mauritzvdworm did in his first post. Apparently what you really wanted was the he do the problem for you.
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