Just explain how one would go about doing this: What's the rule to this?
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Originally Posted by Zanderist Just explain how one would go about doing this: What's the rule to this? You need to use the Quotient Rule: If then .
to solve that you would use th quotient rules as well as the sin and cos rules. so using the quotient rule, fill it all in and solve
Originally Posted by Zanderist Just explain how one would go about doing this: What's the rule to this? this would be: 4cosx(2+cosx) - 4sinx(-sinx) ---------------------------- (2+cosx)^2 You can simplify even if you miss the entire semester. Go for it!!
Originally Posted by harish21 this would be: 4cosx(2+cosx) - 4sinx(-sinx) ---------------------------- (2+cosx)^2 You can simplify even if you miss the entire semester. Go for it!! Yes, now simplify it.
tan(x)-5 -------- sec(x) This some how turns into, -(tan(x)^2-5*tan(x)-sec(x)^2) ---------------------------------- sec(x) I don't see how the quotient rule gives me that.
Originally Posted by Zanderist tan(x)-5 -------- sec(x) This some how turns into, -(tan(x)^2-5*tan(x)-sec(x)^2) ---------------------------------- sec(x) I don't see how the quotient rule gives me that. I would actually have done: .
Originally Posted by Zanderist tan(x)-5 -------- sec(x) This some how turns into, -(tan(x)^2-5*tan(x)-sec(x)^2) ---------------------------------- sec(x) I don't see how the quotient rule gives me that. tan(x)-5 / secx = (sinx - 5cosx) [ Reason: tanx=sinx/cosx and secx=1/cosx] Derivate this and you get cosx + 5 sinx
Last edited by harish21; February 28th 2010 at 09:56 AM. Reason: mistake in the previous post