LinkBack URL
About LinkBacksIn a certain culture of bacteria, the number of bacteria increased sixfold in 10h. Assuming natural growth, how long did it take for their number to double?
This is classic exponential growth so use the equation A(t) = A_0e^{kt}Originally Posted by Abalo
where:
= Amount at time t
= Amount at time 0/initial amount
= growth constant
= time
By definition the amount at time 0 is equal to
If the increase is sixfold after ten hours we get the following:
which is equal to
From there you can find k
Once you know your value of k find t using the rearranged equation below and that
![t = \frac{1}{k} \left[ \ln (A_t) - \ln (A_0)\right]](http://latex.codecogs.com/png.latex?t = \frac{1}{k} \left[ \ln (A_t) - \ln (A_0)\right])
  |
