The question says comupte the area by integrating, BUT in order to integrate I have to find the find the intersaction points. How do I find the intersection point of this CUBIC FUNCTION-- X^3+X^2-12. Can anyone help me please?
Additional Info--
Well it's area between two curves problem. So In order to do that I have to figure out where the two curves intersect over y- axis.
I set functions y= x^3-6 and y=x^2+6 equal to each other to find the intersection points.
then I got x^3-x^2-12=0
Now I don't know how to solve. I was thinking about quadratic formula, but not sure if that can be used in this case.
Even if it can, Is there any other ways to factor this x^3-x^2-12=0 function to find the x values?
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Well it's area between two curves problem. So In order to do that I have to figure out where the two curves intersect over y- axis.
I set functions y= x^3-6 and y=x^2+6 equal to each other to find the intersection points.
then I got x^3-x^2-12=0
Now I don't know how to solve. I was thinking about quadratic formula, but not sure if that can be used in this case.
Even if it can, Is there any other ways to factor this x^3-x^2-12=0 function to find the x values?