http://euler.vaniercollege.qc.ca/web...e4ff233941.png

I'm lost as to how to go about solving this. u = 4x and du = 4 dx but beyond that I'm stumped. That constant in the denominator confuses me.

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- February 24th 2010, 08:39 PMArchduke01Problem with exponential integralhttp://euler.vaniercollege.qc.ca/web...e4ff233941.png

I'm lost as to how to go about solving this. u = 4x and du = 4 dx but beyond that I'm stumped. That constant in the denominator confuses me.

- February 24th 2010, 08:49 PMTheEmptySet
- February 24th 2010, 08:51 PMArchduke01
- February 24th 2010, 08:57 PMTheEmptySet
- February 24th 2010, 09:03 PMArchduke01
- February 24th 2010, 09:14 PMProve It
- February 24th 2010, 09:19 PMArchduke01
- February 24th 2010, 09:24 PMProve It
Because if you have an integral of the form

you make the substitution .

This is so that you can factor out the and then make use of the identity .

And since the derivative of is , this also means that the will be eliminated (as you will end up with them on the top and bottom).