http://euler.vaniercollege.qc.ca/web...e4ff233941.png

I'm lost as to how to go about solving this. u = 4x and du = 4 dx but beyond that I'm stumped. That constant in the denominator confuses me.

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- Feb 24th 2010, 07:39 PMArchduke01Problem with exponential integralhttp://euler.vaniercollege.qc.ca/web...e4ff233941.png

I'm lost as to how to go about solving this. u = 4x and du = 4 dx but beyond that I'm stumped. That constant in the denominator confuses me.

- Feb 24th 2010, 07:49 PMTheEmptySet
- Feb 24th 2010, 07:51 PMArchduke01
- Feb 24th 2010, 07:57 PMTheEmptySet
- Feb 24th 2010, 08:03 PMArchduke01
- Feb 24th 2010, 08:14 PMProve It
- Feb 24th 2010, 08:19 PMArchduke01
- Feb 24th 2010, 08:24 PMProve It
Because if you have an integral of the form

you make the substitution .

This is so that you can factor out the and then make use of the identity .

And since the derivative of is , this also means that the will be eliminated (as you will end up with them on the top and bottom).