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Math Help - How to solve this Integral problem? Some one please help.

  1. #1
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    How to solve this Integral problem? Some one please help.

    I am trying to solve this integral problem, but really can't figure it out. Some one please help me----

    Integral (2x^3-7x^2+7x)/(2x-5)

    The ans is-- [IMG]file:///C:/Users/SOWMIT%7E1/AppData/Local/Temp/moz-screenshot-1.png[/IMG][IMG]file:///C:/Users/SOWMIT%7E1/AppData/Local/Temp/moz-screenshot.png[/IMG]
    Attached Thumbnails Attached Thumbnails How to solve this Integral problem? Some one please help.-ans.gif  
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  2. #2
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    Do you know how to do long division of polynomials?
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  3. #3
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    Yes, so do I do long division and divide them up into small parts?
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  4. #4
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    if you divide it all by 2x-5 you get
    x^2-x+6-(30/2x-5) and you should be able to integrate this.
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  5. #5
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    Quote Originally Posted by skboss View Post
    Yes, so do I do long division and divide them up into small parts?
    Yes.
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  6. #6
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    Quote Originally Posted by skboss View Post
    Yes, so do I do long division and divide them up into small parts?
    \frac{2x^3-7x^2+7x}{2x-5}=x^2-x+1+\frac{5}{2x-5}
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  7. #7
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    Quote Originally Posted by ione View Post
    \frac{2x^3-7x^2+7x}{2x-5}=x^2-x+1+\frac{5}{2x-5}
    Nice, I made a mistake by rushing it.
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