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Math Help - differention (equation of tangent)

  1. #1
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    differention (equation of tangent)

    Using differentiation find the equation of the tangent to the curve
    y= 4 + ln(x+1) at the point where x=0

    Thanks!
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  2. #2
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    Quote Originally Posted by Oasis1993 View Post
    Using differentiation find the equation of the tangent to the curve
    y= 4 + ln(x+1) at the point where x=0

    Thanks!
    Have you found the derivative of 4+ ln(x+1)?
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  3. #3
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    i think im doing the mistake there.
    is the derivative of y= 4+ ln(x+1) 1/(x+1) or 4/ (x+1) ?
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  4. #4
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    Quote Originally Posted by Oasis1993 View Post
    i think im doing the mistake there.
    is the derivative of y= 4+ ln(x+1) 1/(x+1) or 4/ (x+1) ?
    Neither. The derivative of "4" is "0" and the derivative of "ln(x+1)" is " \frac{1}{x+1}". The derivative of the sum f+ g is f'+ g' so the derivative of 4+ ln(x+1) is 0+ \frac{1}{x+1}= \frac{1}{x+1}.
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  5. #5
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    yes the derivative of the equation is 1 / (x+1).
    But what do i do to get the equation of the tangent?
    I put 0 instead of x which gives 1?..and then?
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  6. #6
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    The first thing you should have learned about the derivative is that it generalizes the slope of a line.

    The slope of the tangent line to a curve at a point is the derivative at that point.
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