Find the area bounded by the graph of each of the following functions, the x-axis and the given co-ordinates. Sketch the graph in case.
f(x)=2-x-x^2 ; x=0 to x=2.
=(0) - (2(2) - (2)^2/2) - (2)^3/3)
=0 - (-2/3)
Absolute value gives me:
But the answer is not right it is:
I don't get it please help.
February 24th 2010, 12:26 AM
Is the answer right?
February 24th 2010, 02:15 AM
The graph of crosses the x-axis at x= 1. The region bounded by those graphs has a portion above the x-axis and a portion below it. Since area is always positive and integrating a negative function give a negative result the area is