hey totally stuck on this problem! Find the area of the region that is enclosed by the horizontal line y=3 and the parabola y=x^2-1? help would be mucho appreciated! (don't know how to put in squared..new to this!)
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First, look at the graph: Identify the endpoints of the region (I'll call them a and b) and which curve is "above" and which is "below". (I'll call them T(x) for top and B(x) for bottom.) Then we set up the integral: Do you know how to solve this?
nope not really..im really struggling with this..it just doesnt seem to be sinking in!
Where exactly is your problem? Are you saying you do not know how to integrate ? Do you not know that the integral of is ?
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