# Math Help - parabola trouble!

1. ## parabola trouble!

hey totally stuck on this problem!
Find the area of the region that is enclosed by the horizontal line y=3 and the parabola y=x^2-1?

help would be mucho appreciated!
(don't know how to put in squared..new to this!)

2. First, look at the graph:

Identify the endpoints of the region (I'll call them a and b) and which curve is "above" and which is "below". (I'll call them T(x) for top and B(x) for bottom.)

Then we set up the integral:

$\int_a^b \left[T(x) - B(x)\right] dx = \int_{-2}^2 \left[3 - (x^2-1)\right] dx = \int_{-2}^2 (4 - x^2) \, dx$

Do you know how to solve this?

3. ## eek!

nope not really..im really struggling with this..it just doesnt seem to be sinking in!

4. Where exactly is your problem? Are you saying you do not know how to integrate $4- x^2$? Do you not know that the integral of $x^n$ is $\frac{1}{n+1}x^{n+1}+ a constant$?