[SOLVED] Find Critical Points

**vinson24** · February 23rd 2010, 12:11 PM

$f(x)={ln(2x)}/{x} ;[1,e]$
Find the critical points
I used the quotient rule and got
$f'(x)= {-ln(2x)}/{x^{2}}$
and now i equal the equation to zero and them im stuck cant solve it

**icemanfan** · February 23rd 2010, 12:15 PM

This is because

$f'(x) = \frac{1 - \ln (2x)}{x^2}$ .

Try solving it now.

**vinson24** · February 23rd 2010, 12:26 PM

Still not sure. Not sure how what to do with the ln(2x) and the $x^{2}$ on the bottom

**icemanfan** · February 23rd 2010, 12:30 PM

The only way to get $\frac{1 - \ln (2x)}{x^2} = 0$ is to have $1 - \ln (2x) = 0$ or $\ln (2x) = 1$ .

**vinson24** · February 23rd 2010, 12:38 PM

So then I would only have on critical point on that interval?

Thread: [SOLVED] Find Critical Points

LinkBack

Thread Tools

Display

[SOLVED] Find Critical Points

Similar Math Help Forum Discussions

Find the critical points.

Find the critical points of...

Max and Min, Help Cant find the critical points?

Find The Critical Points

[SOLVED] Critical points

Search Tags