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Thread: implicit differentation

  1. February 23rd 2010, 09:15 AM #1
    maybnxtseasn
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    implicit differentation

    implicit differentation
    --------------------
    x²y+y²x=2

    i got (y') = -1/x²

    is that correct?
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  2. February 23rd 2010, 09:41 AM #2
    tonio
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    Quote Originally Posted by maybnxtseasn View Post
    implicit differentation
    --------------------
    x²y+y²x=2

    i got (y') = -1/x²

    is that correct?


    x^2y+xy^2=2\Longrightarrow 2xydx+x^2dy+y^2dx+2xydy=0\Longrightarrow (x^2+2xy)dy =-(2xy+y^2)dx\Longrightarrow y':=\frac{dy}{dx}=-\frac{y(2x+y)}{x(x+2y)} .

    I can't see how you got the result you did.

    Tonio
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