implicit differentation -------------------- x²y+y²x=2 i got (y') = -1/x² is that correct?
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Originally Posted by maybnxtseasn implicit differentation -------------------- x²y+y²x=2 i got (y') = -1/x² is that correct? $\displaystyle x^2y+xy^2=2\Longrightarrow 2xydx+x^2dy+y^2dx+2xydy=0\Longrightarrow (x^2+2xy)dy$ $\displaystyle =-(2xy+y^2)dx\Longrightarrow $ $\displaystyle y':=\frac{dy}{dx}=-\frac{y(2x+y)}{x(x+2y)}$ . I can't see how you got the result you did. Tonio
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